[tex]Q.stress.by@antarapayoga(Karena.mod.yang.setia denagn fansnya)\\\sqrt{125} X\frac{3}{4} +\frac{.... Question from @antarapayoga

May 2022 2 14 Report

[tex]Q.stress.by@antarapayoga(Karena.mod.yang.setia denagn fansnya)\\\sqrt{125} X\frac{3}{4} +\frac{9}{3}[/tex]

Jawaban :

$= 125 \times (\frac{3}{4} + \frac{9}{3} ) \\ = 125 \times ( \frac{9 + 36}{12} ) \\ = 125 \times \frac{45}{12} \\ = \frac{125}{1} \times \frac{45}{12} \\ = \frac{5.625}{12} \\ = \frac{1.875}{4}$

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Kelas : 6

Pelajaran : Matematika

Kategori : Pecahan

Kata Kunci : -

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$\color{blue}\small\boxed{\boxed{\underline{\tt{༺ \: ucᴇʟʟs \: ༻}}}}$

14 votes Thanks 2

GazooRacing03 itu akar -_-

antarapayoga Koreksi

antarapayoga Bang UceLLs

UceLLs yup

UceLLs tak reti, report aj

antarapayoga Ngapain rate jelek

antarapayoga Aku kasih ba karena dikasih rate jelek

UceLLs kok ba

UceLLs gg

antarapayoga Ya ya lah

GazooRacing03

√125 × 3/4 + 9/3

= √5².5 × (3.3)/(4.3) + (9.4)/(3.4)

= 5√5 × 9/12 + 36/12

TUKAR 9/12 KE DEPAN

= 9/12 × ( 5√5 + 4 )

= 3/4 × ( 5√5 + 4 )

0 votes Thanks 1

GazooRacing03 cape jelasin.

GazooRacing03 coba cari akar √125 itu berapa

antarapayoga Ya kan dibulatin

antarapayoga Jadi 11

SasukeUchiha01 bukannya hasilnya 15√5/4 + 3?

antarapayoga Mungkin

SasukeUchiha01 .-. bener gak?

antarapayoga Bentar

antarapayoga Coba report:alasan jawabannya 15√5/4+3

antarapayoga Ok dah di konfirmasi jawaban dia emang benar

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