#3.[tex] \\ [/tex]f(a) = 3a² + a!! - 6f(8) = ...?[tex] \\ [/tex].... Question from @Ciyraa

August 2022 2 21 Report

#3.
[tex] \\ [/tex]
f(a) = 3a² + a!! - 6
f(8) = ...?
[tex] \\ [/tex]

f(a) = 3a² + a!! - 6

f(8) = 3(8)² + 8!! - 6

f(8) = 3(8 × 8) + (8 × 6 × 4 × 2) - 6

f(8) = 3(64) + (48 × 8) - 6

f(8) = 192 + 384 - 6

f(8) = 576 - 6

f(8) = 570

$\colorbox{black}{\color{red}{\boxed{ \boxed{ \color{pink}{\rm{NinmyLovely}}}}}}$

0 votes Thanks 1

ArtX1

$\mathfrak{\bf \sf \tt f(a) = 3a² + a!! - 6}$

$\mathfrak{\bf \sf \tt f(8) = 3(8²) + 8!! - 6}$

$\mathfrak{\bf \sf \tt f(8) = 3(64) + ( 8 × 6 × 4 × 2 ) - 6}$

$\mathfrak{\bf \sf \tt f(8) = 192 + ( 48 × 4 × 2 ) - 6}$

$\mathfrak{\bf \sf \tt f(8) = 192 + ( 192 × 8 ) - 6}$

$\mathfrak{\bf \sf \tt f(8) = 192 + 384 - 6}$

$\mathfrak{\bf \sf \tt f(8) = 576 - 6}$

$\bold{\underline{\green{\mathfrak{\bf \sf \tt f(8) = 570}}}}$

1 votes Thanks 0

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