[tex]\displaystyle\sf\Large\sum\limits_{n=3}^{7}({n}^{2}+3n-2)=...[/tex].... Question from @Corvusion

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June 2022 2 12 Report

[tex]\displaystyle\sf\Large\sum\limits_{n=3}^{7}({n}^{2}+3n-2)=...[/tex]

cacaandikaofficial

$\displaystyle\sf\Large\sum\limits_{n=3}^{7}({n}^{2}+3n-2)$

$= \displaystyle\sf\Large\sum\limits_{n=3}^{7} {n}^{2} + \displaystyle\sf\Large\sum\limits_{n=3}^{7}3n - \displaystyle\sf\Large\sum\limits_{n=3}^{7}2 \\$

$= 135 + 75 - 10$

$= 200$

1 votes Thanks 1

Arysujaya

Jawab:

200

Penjelasan dengan langkah-langkah:

$\Sigma_{n = 3}^7 (n^2 + 3n - 2)\\= (3^2 + 3\cdot 3 - 2) + (4^2 + 3\cdot 4 - 2) + (5^2 + 3\cdot 5 - 2) + (6^2 + 3\cdot 6- 2) + (7^2 + 3\cdot 7 - 2)\\ = 200$