Q. [tex] \\ [/tex]Titik P merupakan pusat bidang lingkaran tutup dari suatu tabung sekaligus puncak .... Question from @Nelsyasj

CeliaClaire

r = 30 ÷ 2 = 15 cm

tinggi

= Ls ÷ πd

= 600π cm² ÷ 30π cm

= 20 cm

Garis lukis kerucut

$\tt = \sqrt{ {t}^{2} + {r}^{2} }$

$\tt = \sqrt{ {20}^{2} + {15}^{2} }$

$\tt = \sqrt{400 + 225}$

$\tt = \sqrt{625}$

= 25 cm

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khadijahamjad12

SOAL 1

___________________________________________

L Selimut Tabung = 2 × π × r × t

600π = 2 × π × 15 × t

600π = 2 × 15π × t

600π = 30π × t

t = 600π ÷ 30π

t = 20 cm

___________________________________________

Garis Pelukis

= √r² + t²

= √15² + 20²

= √225 + 400

= √625

= 25 cm

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SOAL 1

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