Jawab:Hp = {- ³/₂, -1}
Penjelasan:2x² + 5x + 3 = 0 {a ≠ 1}ax² + bx + c = 0a = 2, b = 5, c = 3
∵ a ≠ 1 ∴p+q = b pq = acp+q = 5 pq = 2(3)p+q = 5 pq = 6p = 2, q = 3
ax² + px + qx + c = 0 {a ≠ 1} 2x² + 2x + 3x + 3 = 02x(x+1) + 3(x+1) = 0(2x+3) (x+1) = 02x+3 = 0 x+1 = 02x = -3 x = -1x = - ³/₂ x = -1Hp = {- ³/₂, -1}
atau juga bisa beginiax² + qx + px + c = 0 {a ≠ 1} 2x² + 3x + 2x + 3 = 02x(x+³/₂) + 2(x+³/₂) = 0(x+³/₂) (2x+2) = 0x+³/₂ = 0 2x = -2x = - ³/₂ x = -²/₂x = - ³/₂ x = -1Hp = {- ³/₂, -1}
(xcvi)
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
Jawab:
Hp = {- ³/₂, -1}
Penjelasan:
2x² + 5x + 3 = 0 {a ≠ 1}
ax² + bx + c = 0
a = 2, b = 5, c = 3
∵ a ≠ 1 ∴
p+q = b pq = ac
p+q = 5 pq = 2(3)
p+q = 5 pq = 6
p = 2, q = 3
ax² + px + qx + c = 0 {a ≠ 1}
2x² + 2x + 3x + 3 = 0
2x(x+1) + 3(x+1) = 0
(2x+3) (x+1) = 0
2x+3 = 0 x+1 = 0
2x = -3 x = -1
x = - ³/₂ x = -1
Hp = {- ³/₂, -1}
atau juga bisa begini
ax² + qx + px + c = 0 {a ≠ 1}
2x² + 3x + 2x + 3 = 0
2x(x+³/₂) + 2(x+³/₂) = 0
(x+³/₂) (2x+2) = 0
x+³/₂ = 0 2x = -2
x = - ³/₂ x = -²/₂
x = - ³/₂ x = -1
Hp = {- ³/₂, -1}
(xcvi)