Zapisz słownie:
[tex]3Be(OH)_{2} + P_{4}O_{10} --\ \textgreater \ Be_{3} (PO_{4})_{2} + 3H_{2}O[/tex]
[tex]3Be(OH)_{2} + P_{4}O_{10} --\ \textgreater \ Be_{3} (PO_{4})_{2} + 3H_{2}O[/tex]
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Odpowiedź:
wodorotlenek berylu(II) + tlenek fosforu (V)= fosgoran (V) berylu (II) + woda
Wyjaśnienie: