Q.
[tex] \\ [/tex]
[tex] \huge \mathfrak \color{green}pertanyaan : [/tex]
[tex] \\ [/tex]
[tex] \tt \lim_{x \to2} \sqrt{ \frac{1 \: - \: cos(x - 2)}{2 {x}^{2} \: - 8x \: + \: 8} } = ..[/tex]
[tex] \\ [/tex]
[tex] \huge \mathfrak \color{green}rules : [/tex]
[tex] \\ [/tex]
=> Sertakan Cara.
=> No NGASAL.
=> No copas.
=> RAPI.
[tex] \\ [/tex]
[tex] \tt \tiny \: req \: ?[/tex]
[tex] \\ [/tex]
[tex] \huge \mathfrak \color{green}pertanyaan : [/tex]
[tex] \\ [/tex]
[tex] \tt \lim_{x \to2} \sqrt{ \frac{1 \: - \: cos(x - 2)}{2 {x}^{2} \: - 8x \: + \: 8} } = ..[/tex]
[tex] \\ [/tex]
[tex] \huge \mathfrak \color{green}rules : [/tex]
[tex] \\ [/tex]
=> Sertakan Cara.
=> No NGASAL.
=> No copas.
=> RAPI.
[tex] \\ [/tex]
[tex] \tt \tiny \: req \: ?[/tex]
Insusceptible
Penyelesaian:[tex]\tt \lim_{x \to2} \sqrt{ \frac{1 \: - \: cos(x - 2)}{2 {x}^{2} \: - 8x \: + \: 8} } \\ = \sqrt{ \lim_{x \to2}\frac{1 \: - \: cos(x - 2)}{2 {x}^{2} \: - 8x \: + \: 8}} [/tex]Karena Limit nya menghasilkan angka 0/0 maka fungsi diturunkan.=√(Lim x→2 sin(x-2)/4x-8Tetep 0/0 turunkan lagi=√(Lim x→2 cos(x-2)/4=√(cos(0)/4)=√(1/4)=1/2[tex] \boxed{ \colorbox{black}{ \sf{ \color{lightgreen}{ answered\:by\:Duone}}}} [/tex]
2 votes
Thanks 2