Question

Diketahui vektor [tex]\tt\overrightarrow{a} = \binom{6}{3} \\ [/tex].
Tentukan panjang vektor [tex]\tt\overrightarrow{a} [/tex] .​

Answer 1

[tex]\tt\overrightarrow{a} = \binom{6}{3} \\[/tex][tex] {a}^{2} = {6}^{2} + {3}^{2} [/tex][tex] {a}^{2} = (6 \times 6) + (3 \times 3)[/tex][tex] {a}^{2} = 36 + 9[/tex][tex] {a}^{2} = 45[/tex][tex]a = \sqrt{45} [/tex][tex]a = \sqrt{9 \times 5} [/tex][tex]a = 3 \times \sqrt{5} [/tex][tex]a = 3 \sqrt{5} [/tex][tex]\purple{\boxed{\green{\boxed{\red{\tt{\ \: \red{{» By : \: XxDarknessxX࿐ }}}}}}}}[/tex]