Question

tentukan akar akar persamaan kuadrat dengan cara rumus ABC
[tex] {x}^{2} - x + \frac{1}{4} = 0[/tex]
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Answer 1

Penjelasan dengan langkah-langkah:

x² - x + 1/4 = 0

a = 1 ; b = -1 ; c = 1/4

x = [ -b ± √(b² - 4ac) ]/2a

x = [ -(-1) ± √(-1)² - 4(1)(1/4) ]/2(1)

x = [ 1 + √(1 - 1) ]/2

x = (1 + √0)/2

x = (1 + 0)/2

x = 1/2