Question

Q. angry
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Terlampir-!
[tex] \\ [/tex]
RULES :
[tex] \\ [/tex]
=> Sertakan Cara!
=> No NGASAL!!
=> No Copas!
[tex] \\ [/tex]
​

Answer 1

Jawab:

Penjelasan dengan langkah-langkah:

Titik potong sumbu X = (-5, 0) dan (1, 0)

Titik potong sumbu Y = (0, -2)

Bentuk umum fungsi kuadrat : f(x) = ax² + bx + c

(-5, 0) ⇒ 0 = a(-5)² + b(-5) + c

25a - 5b + c = 0

(1, 0) ⇒ 0 = a(1)² + b(1) + c

a + b + c = 0

(0, -2) ⇒ -2 = a(0)² + b(0) + c

c = -2

25a - 5b - 2 = 0

25a - 5b = 2

a + b - 2 = 0

a + b = 2

25a - 5b = 2

a + b = 2 ⇒ b = 2 - a

25a - 5 (2 - a) = 2

25a - 10 + 5a = 2

30a = 10 + 2

30a = 12

a = 12/30

a = 2/5

b = 2 - (2/5)

b = (10 - 2)/5

b = 8/5

f(x) = x² + x - 2

f(x) = (2/5) (x² + 4x - 5)