Qz(1/10)[tex] \: \: [/tex]12% + ¼ - 125‰ = ....... Question from @ErichelFr

August 2022 2 31 Report

Qz(1/10)
[tex] \: \: [/tex]
12% + ¼ - 125‰ = ...

CeliaClaire

= 12% + ¼ - 125‰

$\tt = \frac{120}{1.000} + \frac{250}{1.000} - \frac{125}{1.000}$

$\tt = \frac{370}{1.000} - \frac{125}{1.000}$

$\tt = \frac{245}{1.000}$

= 245‰

= 24,5%

= 0,245

$\pink{\boxed{\red{\boxed{\purple{\mathfrak{\ast ~ \blue{Celia ~ Claire} ~ \ast}}}}}}$

3 votes Thanks 1

ArtX1

$12\% + \frac{1}{4} - 125‰$

$\frac{12}{100} + \frac{1}{4} - \frac{125}{1000}$

$\frac{12 \times 10}{100 \times 10} + \frac{1 \times 250}{4 \times 250} - \frac{125}{1000}$

$\frac{120}{1000} + \frac{250}{1000} - \frac{125}{1000}$

$\frac{120 + 250 - 125}{1000}$

$\frac{370 - 125}{1000}$

$\frac{245}{1000}$

$\frac{245 \div 5}{1000 \div 5}$

$\frac{49}{200}$

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2 votes Thanks 1

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