Quiz(+50)[tex] \: \: [/tex][tex] \huge \displaystyle \red{\lim_{x \to6} \: \frac{ {x}^{2} + 6x + 3 }.... Question from @ErichelFr

August 2022 2 31 Report

Quiz(+50)
[tex] \: \: [/tex]
[tex] \huge \displaystyle \red{\lim_{x \to6} \: \frac{ {x}^{2} + 6x + 3 }{3x} = ..}[/tex]

!!

Jawaban:

25/6

Penjelasan dengan langkah-langkah:

$= \frac{6 {}^{2} + 6(6) + 3}{3(6)} \\ = \frac{36 + 36 + 3}{18} \\ = \frac{75}{18} \\ = \frac{25}{6}$

11 votes Thanks 17

ArtX1

$\lim_{x \to6} \: \frac{ {x}^{2} + 6x + 3 }{3x}$

$\frac{{6}^{2} + 6(6) + 3}{3(6)}$

$\frac{( 6 × 6 ) + 6(6) + 3}{3(6)}$

$\frac{36 + 36 + 3}{18}$

$\frac{72 + 3}{18}$

$\frac{75}{18}$

$\frac{75 ÷ 3}{18 ÷ 3}$

$\frac{25}{6}$

$1\frac{4}{6}$

7 votes Thanks 13

ErichelFr yakin ?

kelvinho018527 ckck gunakan l'hopital tapi tak tahu syaratnya

kelvinho018527 syarat l'hopital: 0/0, limit kanan kiri sama(limit ada)

ArtX1 tar ;-; aku mau edit dulu

ArtX1 jangan di hapus dulu bang :v

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