tentukan nilai m sehingga pasangan pasangan pecahan berikut senilai!
a.
[tex] a.\frac{16}{24} = \frac{m}{6} \\ b. \frac{m}{28} = \frac{12}{7} \\ c. \frac{5}{m} = \frac{50}{120} \\d. \frac{7}{25} = \frac{21}{m} [/tex]
a.
[tex] a.\frac{16}{24} = \frac{m}{6} \\ b. \frac{m}{28} = \frac{12}{7} \\ c. \frac{5}{m} = \frac{50}{120} \\d. \frac{7}{25} = \frac{21}{m} [/tex]
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