Question

[tex](-6yx)(2x^{2} +x+3)[/tex]
[tex](x+3)(x-4)[/tex]
[tex](x-y)(x^{2} +xy+y^{2})[/tex]
(x+3)(x-3)
por fa ayuda

Answer 1

Respuesta:

[tex]a)( - 6yx)(2 {x}^{2} + x + 3)[/tex]

[tex] = ( - 6yx)(2 {x}^{2} ) + ( - 6yx)(x) + ( - 6yx)(3)[/tex]

[tex] = - 12 {x}^{3} y - 6 {x}^{2} - 18xy[/tex]

[tex]b)(x + 3)(x - 4)[/tex]

[tex] = (x)(x) + (x)( - 4) + (3)(x) + (3)(4)[/tex]

[tex] = {x}^{2} - 4x + 3x - 12[/tex]

[tex] = {x}^{2} - x - 12[/tex]

[tex]c)(x - y)( {x}^{2} + xy + {y}^{2} )[/tex]

[tex] = (x)( {x}^{2} ) + (x)(xy) + (x)( {y}^{2} ) + (y)( {x}^{2} ) + (y)(xy) + (y)( {y}^{2} )[/tex]

[tex] = {x}^{3} + {x}^{2} y + x {y }^{2} - {x}^{2} y - x {y}^{2} + {y}^{3} [/tex]

[tex] = {x}^{3} + {y}^{3} [/tex]

[tex]d)(x + 3)(x - 3)[/tex]

[tex] = (x)(x) + (x)( - 3) + (3)(x) + (3)( - 3)[/tex]

[tex] = {x}^{2} - 3x + 3x - 9[/tex]

[tex] = {x}^{2} - 9[/tex]

Explicación paso a paso:

Espero te ayude :)