Question

Wyznacz miejsce zerowe funkcji:
a) y = -4x + 6
b) y = 5x - 20
c) y = [tex]\frac{1}{2}[/tex] x + 3
d) y = -3x - 27

Answer 1

a)

[tex]y = -4x+6\\\\-4x+6 = 0\\\\-4x = -6 \ \ \ :(-4)\\\\\boxed{x= \frac{6}{4} = 1\frac{1}{2}}[/tex]

b)

[tex]y = 5x - 20\\\\5x-20 = 0\\\\5x = 20 \ \ \ /:5\\\\\boxed{x = 4}[/tex]

c)

[tex]y = \frac{1}{2}x + 3\\\\\frac{1}{2}x +3 = 0\\\\\frac{1}{2}x =-3 \ \ \ |\cdot2\\\\\boxed{x= -6}[/tex]

d)

[tex]y = -3x - 27\\\\-3x-27 = 0\\\\-3x = 27 \ \ \ /:(-3)\\\\\boxed{x = -9}[/tex]