⅘ × ⅔ = ...
[tex] \\ \\ [/tex]
Lim (4x × x + 9)
x → 2
[tex] \\ \\ [/tex]
;-; TvT
[tex] \\ \\ [/tex]
Lim (4x × x + 9)
x → 2
[tex] \\ \\ [/tex]
;-; TvT
SasukeUchiha01
4/5 × ⅔= 4 × 2 / 5 × 3= 8 / 5 × 3= 8/15Lim ( 4x × x + 9 )x → 2= Lim ( 5x + 9 ) x→ 2= 5 × 2 + 9= 10 + 9= 19~Koreksi~⃢~ Opung~⃠⃫⃟⃤᳗᳐
2 votes
Thanks 2