Question

jika [tex]\bf{f\left(x\right)=2x^{2}+16x+32}[/tex]
maka [tex]\bf{f'\left(2\right)=?}[/tex]


[tex]\small\boxed{\tt{Note_{1}=Jawablah\ dengan\ usaha\ sendiri}}[/tex]
[tex]\small\boxed{\tt{Note_{2}=Dilarang\ nyalin\ jawaban\ maupun\ copas\ dari\ web}}[/tex]
[tex]\small\boxed{\tt{Note_{3}=Jaga \ Kesehatan \ yah}}[/tex]



Terimakasih ^^

Answer 1

Jawaban:

f'(2) = 24

Penjelasan dengan langkah-langkah:

f(x) = 2x² + 16x + 32

f'(x) = 2 × 2x¹ + 1 × 16x⁰ + 0

f'(x) = 4x + 16

f'(2) = 4 × 2 + 16

f'(2) = 8 + 16

f'(2) = 24

Answer 2

f(x) = 2x² + 16x + 32

f'(x) = ( 2 × 2 )x^(2-1) + ( 1 × 16 )x^(1-1) + ( 32 × 0 )

f'(x) = 4x¹ + 16x⁰ + 0

f'(x) = 4x + 16(1) + 0

f'(x) = 4x + 16

f'(2) = 4(2) + 16

f'(2) = 8 + 16

f'(2) = 24