Question

Quote.
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f(x) = 1 + 1 + 327(4!)x) × 5x
f(4) = ?
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Answer 1

Diketahui:

f(x) = 1 + 1 + 327(4!)x) × 5x

Ditanya:

f(4) = ?

Dijawab:

• 1 + 1 + 327(4!)x) × 5x
• 2 + 327(4 × 3 × 2 × 1)4) × 5(4)
• 2 + 327(12 × 2)4) × (5 × 4)
• 2 + 327(24)4) × 20
• 2 + 327(24 × 4) × 20
• 2 + 327(96) × 20
• 2 + (327 × 96) × 20
• 2 + 31.392 × 20
• 2 + 627.840
• 627.842

Kesimpulan:

Jadi, hasilnya 627.842

#Koreksi

Answer 2

Diketahui

f(x) = 1 + 1 + 327(4!) x) × 5x

Ditanya

f(4) = ?

Jawab :

f(x) = 1 + 1 + 327(4!)x) × 5x

f(4) = 1 + 1 + 327(4!)4) × 5(4)

f(4) = 1 + 1 + 327( 4 × 3 × 2 ×1 )4) × 5(4)

f(4) = 1 + 1 + 327( 12 × 2 × 1 )4) × 5(4)

f(4) = 1 + 1 + 327( 12 × 2 )4) × 5(4)

f(4) = 1 + 1 + 327(24)4) × 5(4)

f(4) = 1 + 1 + 327( 24 × 4 ) × 5(4)

f(4) = 1 + 1 + 327(96) × 5(4)

f(4) = 1 + 1 + ( 327 × 96 ) × 5(4)

f(4) = 1 + 1 + 31.392 × 5(4)

f(4) = 1 + 1 + 31.392 × ( 5 + 5 + 5 + 5 )

f(4) = 1 + 1 + 31.392 × ( 10 + 5 + 5 )

f(4) = 1 + 1 + 31.392 × ( 10 + 10 )

f(4) = 1 + 1 + 31.392 × 20

f(4) = 1 + 1 + ( 31.392 × 20 )

f(4) = 1 + 1 + 627.840

f(4) = ( 1 + 1 ) + 627.840

f(4) = 2 + 627.840

f(4) = 627.842

Kesimpulan

Jadi, hasil nya adalah 627.842