Q. spm spm spm :-::[tex] \\ [/tex]Keliling bangun di atas adalah ..[tex] \\ [/tex][tex] \tt \: a. \:.... Question from @Nelsyasj

Gusti2601

$\mathbb \color{aqua} \underbrace{JAWABAN}$

C. 108 cm

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$\mathbb \color{gold} \underbrace{RUMUS}$

=> Luas lingkaran :

$\boxed{ \sf L = \pi \times {r}^{2}}$

$\\$

=> Luas ½ Lingkungan :

$\small \boxed {\sf L = \frac{1}{2} \times \pi \times {r}^{2}}$

$\\$

=> Keliling Lingkaran :

$\boxed{ \sf K = 2 \times \pi \times r}$

$\boxed{ \sf K = \pi \times d}$

$\\$

=> Keliling ½ Lingkaran :

$\small \boxed{ \sf K = ( \frac{1}{2} \times \pi \times d) + d}$

$\boxed{\sf K = (\pi \times r) + d}$

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$\mathbb \color{orange} \underbrace{PENYELESAIAN}$

$\sf K = ( \frac{1}{2} \times \pi \times d) + d$

$\sf K = ( \frac{1}{ \xcancel2} \times \frac{ \xcancel{22} \: {}^{11} }{ \cancel7 \: \: \: } \times \cancel{42} \: {}^{6} ) + 42$

$\sf K = (1 \times 11 \times 6) + 42$

$\sf K = 66 + 42$

$\sf K = \bold{108 \: cm}$

$\\ \\ \huge \color{lightgreen} \xrightarrow \textsf{\textbf{cara lain : }} \\ \\$

$\sf K = (\pi \times r) + d$

$\sf K = ( \frac{22}{ \cancel7} \times \cancel{21} \: {}^{3} ) + 42$

$\sf K = (22 \times 3) + 42$

$\sf K = 66 + 42$

$\sf K = \bold{108 \: cm}$

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$\mathbb \color{red} \underbrace{KESIMPULAN}$

Jadi, keliling bangun diatas adalah 108 cm

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2 votes Thanks 4

Jawaban :

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