Q. last bsok pagi spam Q ez lg ( klo g bngn ksiangan ) _/\_[tex] \\ [/tex][tex] \tt \int(8 {x}^{3} -.... Question from @Nelsyasj

May 2022 2 8 Report

Q. last bsok pagi spam Q ez lg ( klo g bngn ksiangan ) _/\_
[tex] \\ [/tex]
[tex] \tt \int(8 {x}^{3} - {x}^{2} + 4)dx = ..[/tex]
[tex] \\ [/tex]
RULES ✏ :
[tex] \\ [/tex]
➪ Sertakan Cara-!
➪ No Ngasal-!
➪ No Copas-!
➪ Rapi.

Procyonion

~Integral Tak Tentu

Rumus Integral/Anti turunan:

$\displaystyle\sf\int{ax}^{n}~dx=\frac{a}{n+1}{x}^{n+1}~,~n≠-1$

______________

$\displaystyle\sf\int({8x}^{3}-{x}^{2}+4)~dx$

$\sf=\frac{8}{3+1}{x}^{3+1}-\frac{1}{2+1}{x}^{2+1}+\frac{4}{0+1}{x}^{0+1}+C$

$\sf=\frac{\cancel{8}}{\cancel{4}}{x}^{4}-\frac{1}{3}{x}^{3}+\frac{4}{1}{x}^{1}+C$

$\sf={2x}^{4}-\frac{1}{3}{x}^{3}+4x+C$

MathraraX ._." rara g percaya kaka kelas 6 sd T-T soalnya masa bisa pelajaran sma

Procyonion belajar dri yt kak

MathraraX ._." rara belajar di yt ga bisa² tuh

Procyonion tunggu pas sma dh bisa tuh kyaknya

MathraraX ._. hooh hiks T-T

MathraraX As..... // T-T ndak bisa bambank non muslim._.

Anthology

Jawaban:

Integral Tak Tentu

$\int \: ay {}^{n} \: dy \: \rightarrow \: \frac{ {ay}^{n + 1} }{n + 1} + C \\$

Pembahasan

$\int \: (8 {x}^{3} - {x}^{2} + 4) \: dx \\$

$\int \: \frac{8 {x}^{3 + 1} }{(3 + 1)} - \frac{ {x}^{2 + 1} }{(2 + 1)} + 4x \: dx \\$

$= \frac{8 {x}^{4} }{4} - \frac{ {x}^{3} }{3} + 4x + C \\$

$= 2 {x}^{4} - \frac{1}{3} {x}^{3} + 4x + C \\$

Jadi, hasil dari $\int \: (8 {x}^{3} - {x}^{2} + 4) \: dx \\$ adalah $2 {x}^{4} - \frac{1}{3} {x}^{3} + 4x + C$ .

devonmarcelus952 @ahmad536399 bjir

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