Odpowiedź:
[tex]log_{\sqrt{2} } 16\sqrt{2} = x[/tex] ⇔ ( √2 )[tex]^x = 16\sqrt{2}[/tex]
([tex]\sqrt{2} )^x = (\sqrt{2} )^8*\sqrt{2} = ( \sqrt{2} )^9[/tex]
x = 9
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Szczegółowe wyjaśnienie:
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Odpowiedź:
[tex]log_{\sqrt{2} } 16\sqrt{2} = x[/tex] ⇔ ( √2 )[tex]^x = 16\sqrt{2}[/tex]
([tex]\sqrt{2} )^x = (\sqrt{2} )^8*\sqrt{2} = ( \sqrt{2} )^9[/tex]
x = 9
========
Szczegółowe wyjaśnienie: