[tex]\frac{2 \sqrt{3} \times 3 \sqrt{2}}{12 \sqrt{5}} = \frac{6 \sqrt{6}}{12 \sqrt{5}} [/tex]
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Aljabar
Merasionalkan Penyebut
√a × √b = √(a × b)
√a × √a = a
•
[tex] \begin{aligned} \frac{ 2 \sqrt{3} \: \times \: 3 \sqrt{2} }{ 12 \sqrt{5} }&= \frac{ \sqrt{3 \times 2} }{2 \sqrt{5} } \: \times \: \frac{ \sqrt{5} }{ \sqrt{5} } \\ \\ &= \frac{ \sqrt{6 \times 5} }{2 \times 5} \\ \\ &= \frac{ \sqrt{30} }{10} \end{aligned}[/tex]
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Verified answer
[tex]\frac{2 \sqrt{3} \times 3 \sqrt{2}}{12 \sqrt{5}} = \frac{6 \sqrt{6}}{12 \sqrt{5}} [/tex]
PEMBAHASAN
Aljabar
Merasionalkan Penyebut
√a × √b = √(a × b)
√a × √a = a
•
[tex] \begin{aligned} \frac{ 2 \sqrt{3} \: \times \: 3 \sqrt{2} }{ 12 \sqrt{5} }&= \frac{ \sqrt{3 \times 2} }{2 \sqrt{5} } \: \times \: \frac{ \sqrt{5} }{ \sqrt{5} } \\ \\ &= \frac{ \sqrt{6 \times 5} }{2 \times 5} \\ \\ &= \frac{ \sqrt{30} }{10} \end{aligned}[/tex]