Penjelasan dengan langkah-langkah:
DEFERENSIAL
y = 2x² + 4x + 16
y' = 2(2x²-¹) + 4x¹-¹ + 0
y' = 2(2x) + 4(x^0)
y' = 4x + 4
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Penjelasan dengan langkah-langkah:
DEFERENSIAL
y = 2x² + 4x + 16
y' = 2(2x²-¹) + 4x¹-¹ + 0
y' = 2(2x) + 4(x^0)
y' = 4x + 4
y' = 4(x + 1) ✔