..
[tex]3x {}^{2} - 2x - 1 = 0[/tex]
[tex](3x + 1)(x - 1) = 0[/tex]
[tex]x_{1} = - \frac{1}{3} \: \vee \: x_{2} = 1[/tex]
[tex] \alpha = - \frac{1}{3} \\ \beta = 1[/tex]
[tex] \frac{ \alpha }{ \beta } + \frac{ \beta }{ \alpha } = \frac{( - \frac{1}{3} )}{1} + \frac{1}{( - \frac{1}{3} )} [/tex]
[tex]~~~~~~~~~~~~= - \frac{1}{3} - 3[/tex]
[tex]~~~~~~~~~~~~= - \frac{10}{3} [/tex]
[tex]~~~~~~~~~~~~= - 3 \frac{1}{3} [/tex]
[tex]\begin{array}{lr}\texttt{Selamat Menunaikan Ibadah Puasa}\end{array}[/tex]
[tex]\boxed{\colorbox{ccddff}{Answered by Danial Alf'at | 27 - 03 - 2023}}[/tex]
Jawaban:
untuk soal di gambar
-10/3
untuk di tulisan
-11/6
Penjelasan dengan langkah-langkah:
terlampir
maaf jika salah
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Verified answer
Persamaan Kuadrat
..
[tex]3x {}^{2} - 2x - 1 = 0[/tex]
[tex](3x + 1)(x - 1) = 0[/tex]
[tex]x_{1} = - \frac{1}{3} \: \vee \: x_{2} = 1[/tex]
[tex] \alpha = - \frac{1}{3} \\ \beta = 1[/tex]
..
[tex] \frac{ \alpha }{ \beta } + \frac{ \beta }{ \alpha } = \frac{( - \frac{1}{3} )}{1} + \frac{1}{( - \frac{1}{3} )} [/tex]
[tex]~~~~~~~~~~~~= - \frac{1}{3} - 3[/tex]
[tex]~~~~~~~~~~~~= - \frac{10}{3} [/tex]
[tex]~~~~~~~~~~~~= - 3 \frac{1}{3} [/tex]
..
[tex]\begin{array}{lr}\texttt{Selamat Menunaikan Ibadah Puasa}\end{array}[/tex]
[tex]\boxed{\colorbox{ccddff}{Answered by Danial Alf'at | 27 - 03 - 2023}}[/tex]
Jawaban:
untuk soal di gambar
-10/3
untuk di tulisan
-11/6
Penjelasan dengan langkah-langkah:
terlampir
maaf jika salah