Question

Qz 76/∞
[tex] f(x) = \bold{x {}^{2} \div x + 4x {}^{5} \times x {}^{3} }[/tex]
[tex]f(x) = \bold{4}[/tex]
→ Gunakan cara
→ No asal​

Answer 1

Penjelasan dengan langkah-langkah:

f(x)=x²:x+4x⁵ x x³

f(x)=4

.

x²-¹ +4x⁵. x³=4

x+4x⁵+³=4

x+4x⁸=4

4x⁸+x-4=0

a =4, b=1, c=-4

.

x1,2 = (-b ±√b²-4ac)/2a

x1,2=(-1±√(1² -4(4)(-4))/2(4)

x1,2=(-1±√(1+64))/8

x1,2=(-1±√65)/8

solusi:

x1 =(-1+√65)/8

x2=(-1-√65)/8