Question

Jika [tex]\sf tanx= \dfrac{1}{3}[/tex], maka nilai dari [tex]\sf \dfrac{5sinx ~+~ 6cosx}{2cosx~-~3sinx}[/tex] adalah....​

Answer 1

Verified answer

(5sinx + 6cosx) / (2cosx - 3sinx)

tanx = 1/3

sinx/cosx = 1/3

cosx = 3sinx

substitusikan nilai cosx

(5sinx + 6(3sinx)) / (2(3sinx) - 3sinx)

(5sinx + 18sinx) / (6sinx - 3sinx)

(23sinx) / (3sinx)

= 23/3