December 2023 1 8 Report
[tex]x^{2} \sqrt{x} \lim_{n \to \infty} a_n \sqrt{x} \pi \neq \lim_{n \to \infty} a_n \int\limits^a_b {x} \, dx \geq \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right][/tex]

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