resuelve las ecuaciones 1 y 2
[tex]a + ( - \frac{8}{3} ) = [/tex]
[tex]2y + ( - \frac{5}{4} ) = [/tex]
[tex]a + ( - \frac{8}{3} ) = [/tex]
[tex]2y + ( - \frac{5}{4} ) = [/tex]
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3a-8
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3
Explicación paso a paso:
8y-5
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4
Explicación paso a paso:
a)
[tex]a + ( \frac{ - 8}{3} ) \\ a - \frac{8}{3} \\ \frac{3a - 8}{3} [/tex]
b)
[tex]2y + ( \frac{ - 5}{4} ) \\ 2y - \frac{5}{4} \\ \frac{8y - 5}{4} [/tex]