ΗΘΙΑ
procedimiento :
[tex]\frac{x+1}{2} +\frac{1}{3} -\frac{1}{3} =2x-\frac{1}{3}[/tex]
[tex]\frac{x+1}{2} =2x-\frac{1}{3}[/tex]
[tex]\frac{x+1}{2} .2=2x.2-\frac{1}{3} .2[/tex]
[tex]x+1=4x-\frac{2}{3}[/tex]
[tex]x+1-1=4x-\frac{2}{3} -1[/tex]
[tex]x=4x-\frac{5}{3}[/tex]
[tex]x-4x=4x-\frac{5}{3} -4x[/tex]
[tex]-3x=-\frac{5}{3}[/tex]
[tex]-3x/3=-5/3/3[/tex]
[tex]x=\frac{5}{9}[/tex]
el resutado es la C x=5/9
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Verified answer
ΗΘΙΑ
procedimiento :
[tex]\frac{x+1}{2} +\frac{1}{3} -\frac{1}{3} =2x-\frac{1}{3}[/tex]
[tex]\frac{x+1}{2} =2x-\frac{1}{3}[/tex]
[tex]\frac{x+1}{2} .2=2x.2-\frac{1}{3} .2[/tex]
[tex]x+1=4x-\frac{2}{3}[/tex]
[tex]x+1-1=4x-\frac{2}{3} -1[/tex]
[tex]x=4x-\frac{5}{3}[/tex]
[tex]x-4x=4x-\frac{5}{3} -4x[/tex]
[tex]-3x=-\frac{5}{3}[/tex]
[tex]-3x/3=-5/3/3[/tex]
[tex]x=\frac{5}{9}[/tex]
el resutado es la C x=5/9
salu2!!