separamos y resolvemos:
a) [tex]2\sqrt{45}=2\sqrt{9*5}=2*3\sqrt{5} =6\sqrt{5} \\[/tex]
b)[tex]3\sqrt{80}=3\sqrt{16*5}=3*4\sqrt{5} =12\sqrt{5}[/tex]
c)[tex]48\sqrt{180}=48\sqrt{9*20}=48*3\sqrt{4*5} =144*2\sqrt{5} =288\sqrt{5}[/tex]
resolucion:
[tex]6\sqrt{5} +12\sqrt{5} -288\sqrt{5}=18\sqrt{5}-288\sqrt{5} =-270\sqrt{5}[/tex]
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Verified answer
separamos y resolvemos:
a) [tex]2\sqrt{45}=2\sqrt{9*5}=2*3\sqrt{5} =6\sqrt{5} \\[/tex]
b)[tex]3\sqrt{80}=3\sqrt{16*5}=3*4\sqrt{5} =12\sqrt{5}[/tex]
c)[tex]48\sqrt{180}=48\sqrt{9*20}=48*3\sqrt{4*5} =144*2\sqrt{5} =288\sqrt{5}[/tex]
resolucion:
[tex]6\sqrt{5} +12\sqrt{5} -288\sqrt{5}=18\sqrt{5}-288\sqrt{5} =-270\sqrt{5}[/tex]