Hola, me podrían ayudar con estos ejercicios porfavor
[tex](4pq {3} + 3pq{2}) {3} [/tex]
[tex](0.3a - 5.6b{2} c) {3} [/tex]
[tex]( \frac{3}{2} xy - \frac{1}{3}yz) {3}[/tex]
[tex](4pq {3} + 3pq{2}) {3} [/tex]
[tex](0.3a - 5.6b{2} c) {3} [/tex]
[tex]( \frac{3}{2} xy - \frac{1}{3}yz) {3}[/tex]
Explicación paso a paso:
Binomio al cubo:
(a ± b)³ = a³ ± 3a²b + 3ab² ± b³
(4pq³ +3pq²)³ = (4pq³)³ +3⋅(3pq²) (4pq³)² +3⋅(3pq²)² (4pq³) +(3pq² )³
(4pq³ +3pq²)³ = 64p³q⁹+144p³q⁸ +108p³q⁷ +27p³q⁶
(0.3a-5.6b² c)³ = (3/10a)³-3⋅(3/10a²) (28/5b² c)² +3⋅(3/10a)² (28/5b² c) -(28/5b² c )³
(0.3a+5.6b² c)³ = 0.027a³ - 1.512a²b²c + 28.224ab⁴c² - 175.616b⁶c³
(3/2xy - 1/3yz)³ = (3/2xy)³ -3⋅(3/2xy) (1/3yz)² +3⋅(3/2xy)² (1/3yz) -(1/3yz)³
(3/2xy - 1/3yz)³ = 27/8x³y³ - 9/4y³x²+ 1/2y³xz² -1/27y³z³