September 2023 1 13 Report
Me ayudan con estas es importante el procedimiento porque el maestro lo exigio
5[tex]\frac{3}{4}[/tex] x [tex]\frac{1}{2} =[/tex]
8 [tex]\frac{6}{10} x \frac{3}{7}[/tex] =
2[tex]\frac{5}{6}[/tex] x 2 [tex]\frac{4}{8} =[/tex]
6 [tex]\frac{8}{9}[/tex] x [tex]\frac{1}{11} =[/tex]

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