Odpowiedź:
[tex] \frac{4x - 12}{2 {x}^{2} - 12x + 18 } = \frac{4(x - 3)}{2( {x}^{2} - 6x + 9) } = \frac{4(x - 3)}{2 {(x - 3)}^{2} } = \frac{2(x - 3)}{ {(x - 3)}^{2} } = \frac{2}{x - 3} [/tex]
[tex] \frac{3x - 9}{2 {x}^{2} - 5x - 3 } = \frac{3(x - 3)}{2 {x}^{2} - 2x - 3x - 3 } = \frac{3(x - 3)}{2x(x - 1) - 3(x + 1)} [/tex]
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Odpowiedź:
[tex] \frac{4x - 12}{2 {x}^{2} - 12x + 18 } = \frac{4(x - 3)}{2( {x}^{2} - 6x + 9) } = \frac{4(x - 3)}{2 {(x - 3)}^{2} } = \frac{2(x - 3)}{ {(x - 3)}^{2} } = \frac{2}{x - 3} [/tex]
[tex] \frac{3x - 9}{2 {x}^{2} - 5x - 3 } = \frac{3(x - 3)}{2 {x}^{2} - 2x - 3x - 3 } = \frac{3(x - 3)}{2x(x - 1) - 3(x + 1)} [/tex]