Question

Kuis:
{q > 0}
[tex]p^{^plog(q)}=......[/tex]

Answer 1

[tex] {p}^{ {{\rm{log}}_p}q} = [/tex]

[tex]{{ \rm{log}}_p}p·q = [/tex]

[tex]1·q = [/tex]

[tex]q[/tex]