[tex] \frac{ {2}^{3 + n} \times {4}^{2n - 1} }{ {2}^{5n} } \\ = \frac{ {2}^{3 + n} \times {2}^{2(2n - 1)} }{ {2}^{5n} } \\ = \frac{ {2}^{3 + n} \times {2}^{4n - 2} }{ {2}^{5n} } \\ = {2}^{3 + n + 4n - 2 - 5n} \\ = {2}^{1 } \\ = 2[/tex]
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Penyelesaian :
[tex] \frac{ {2}^{3 + n} \times {4}^{2n - 1} }{ {2}^{5n} } \\ = \frac{ {2}^{3 + n} \times {2}^{2(2n - 1)} }{ {2}^{5n} } \\ = \frac{ {2}^{3 + n} \times {2}^{4n - 2} }{ {2}^{5n} } \\ = {2}^{3 + n + 4n - 2 - 5n} \\ = {2}^{1 } \\ = 2[/tex]
Lama gak jawab :)