Materi : Bentuk Akar dan Pangkat
[tex][tex] \sf( \frac{3 {p}^{2}q }{ {q}^{ - 1} } )^{ - 1} = ...[/tex][/tex]
[ ( 3p²q )/q-¹ ]-¹
= q-¹/( 3p²q )
= 1/( 3p²q¹+¹ )
= 1/( 3p²q² )
Semoga bisa membantu
[tex] \boxed{ \colorbox{darkblue}{ \sf{ \color{lightblue}{ answered\:by\: BLUEBRAXGEOMETRY}}}} [/tex]
[tex](\frac{3 {p}^{2}q }{ {q}^{ - 1} } )^{ - 1}[/tex]
=q^-1/3p²q
=1/3p²q×q
=1/3p²q²
Semoga bermanfaat
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Materi : Bentuk Akar dan Pangkat
[tex][tex] \sf( \frac{3 {p}^{2}q }{ {q}^{ - 1} } )^{ - 1} = ...[/tex][/tex]
[ ( 3p²q )/q-¹ ]-¹
= q-¹/( 3p²q )
= 1/( 3p²q¹+¹ )
= 1/( 3p²q² )
Semoga bisa membantu
[tex] \boxed{ \colorbox{darkblue}{ \sf{ \color{lightblue}{ answered\:by\: BLUEBRAXGEOMETRY}}}} [/tex]
Penyelesaian
[tex](\frac{3 {p}^{2}q }{ {q}^{ - 1} } )^{ - 1}[/tex]
=q^-1/3p²q
=1/3p²q×q
=1/3p²q²
Semoga bermanfaat