kak tolong bantu jawabin
[tex] \binom{ {p}^{ - 4 } {q}^{2} }{ {p}^{3} {q}^{ - 1} } {}^{3 \: } = [/tex]
[tex] \binom{ {p}^{ - 4 } {q}^{2} }{ {p}^{3} {q}^{ - 1} } {}^{3 \: } = [/tex]
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Materi : Bentuk Akar dan Pangkat
[ ( p-⁴q² )/( p³q-¹ ) ]³
= [ q²+¹/p³+⁴ ]³
= [ q³/p⁷ ]³
= q⁹/p²¹
Semoga bisa membantu
[tex] \boxed{ \colorbox{darkblue}{ \sf{ \color{lightblue}{ answered\:by\: BLUEBRAXGEOMETRY}}}} [/tex]
Penyelesaian
(p^-4q²/p³q^-1)³
=(p^-4 × p^-3 × q² × q¹)³
=(p^-7 × q³)³
=(q³/p⁷)³
=q⁹/p²¹
Semoga bermanfaat