Question

Nyatakan bilangan berikut dalam bilangan berpangkat sederhana.
[tex]a. \: \frac{1}{216} [/tex]
[tex]b. \: \frac{1}{ {25x}^{6} } [/tex]
[tex]c. \: \frac{ {6x}^{5 } {y}^{2} }{ {(2xy)}^{3} } [/tex]
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Answer 1

Verified answer

[tex]\begin{aligned} \sf a. \: \frac{1}{216}&= \sf \frac{1}{ {6}^{3} } = {6}^{ - 3} \end{aligned}[/tex]

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[tex]\begin{aligned} \sf b. \: \frac{1}{ {25x}^{6} } &= \sf \frac{1}{25} \times \frac{1}{ {x}^{6} } \\ \sf &= \sf \frac{1}{ {5}^{2} } \times \frac{1}{ {x}^{6} } \\ \sf &= \sf {5}^{ - 2} {x}^{ - 6} \end{aligned}[/tex]

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[tex]\begin{aligned} \sf c. \: \frac{ {6x}^{5 } {y}^{2} }{ {(2xy)}^{3} } &= \sf \frac{ {6x}^{5 } {y}^{2} }{ { {2}^{3} {x}^{3} {y}^{3}}}\\ \sf &= \sf \frac{ {6x}^{5 } {y}^{2} }{ {8 {x}^{3} {y}^{3}}} \\ \sf &= \sf \frac{6}{8} \: {x}^{5 - 3} {y}^{2 - 3} \\ \sf &= \sf \frac{3}{4} {x}^{2} {y}^{ - 1} \end{aligned}[/tex]