July 2023 1 3 Report
a) -4+3-2+7=

b) 7+2x4=

[tex]d)10 - 36 \div 4.3 = [/tex]

[tex]e) {2}^{3} \div 4 + 6.3 = [/tex]

[tex]f) -40 - 3(4 - 8)^2=[/tex]


[tex]g) 18 ÷[ 9-2^3 ] + (-3) =[/tex]


[tex]h) 2 ({4}^{2} - 6( \sqrt{16 } - (2 -4)) + \sqrt[3]{ - 27} = [/tex]



[tex]i) \frac{12 - (4 - 6) ^{2} }{6 + {4}^{2} \div {2}^{2} } \ \textless \ br /\ \textgreater \ [/tex]



[tex]j)-2 \sqrt{4^2-3.4+ 10 ÷ 2} =[/tex]


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