July 2023 2 7 Report
una ayuda con procedimientos y doy corona

[tex] \frac{7}{8} + \frac{2}{5} \times ( \frac{10}{3} \times (1 + \frac{1}{2} ) \div \frac{3}{2} ) - \frac{4}{3} \div \frac{8}{3} [/tex]

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