[tex]\geq x^{2} x^{2} \sqrt[n]{x} \alpha \sqrt[n]{x}[/tex].... Question from @camivalen1812

July 2023 1 5 Report

[tex]\geq x^{2} x^{2} \sqrt[n]{x} \alpha \sqrt[n]{x}[/tex]

Respuesta:

que

Explicación paso a paso:

0 votes Thanks 0

" Life is not a problem to be solved but a reality to be experienced! "