[tex]\geq x^{2} x^{2} \sqrt[n]{x} \alpha \sqrt[n]{x}[/tex].... Question from @camivalen1812

July 2023 1 3 Report

[tex]\geq x^{2} x^{2} \sqrt[n]{x} \alpha \sqrt[n]{x}[/tex]

Respuesta:

que

Explicación paso a paso:

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