Question

Tentukan nilai x! Mohon bantuannya, terimakasih
[tex]4 \sqrt{ {x}^{8} } = 25[/tex]
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Answer 1

Penjelasan dengan langkah-langkah:

[tex]4 \sqrt{ {x}^{8} } = 25 \\ \sqrt{ {x}^{8} } = \frac{25}{4} \\ {x}^{ \frac{8}{2} } = \frac{25}{4} \\ {x}^{4} = \frac{25}{4} \\ {x}^{2} = \sqrt{ \frac{25}{4} } \\ {x}^{2} = \frac{5}{2} \\ x = \sqrt{ \frac{5}{2} } = \frac{ \sqrt{5} }{ \sqrt{2} } = \frac{ \sqrt{5} }{ \sqrt{2} } \times \frac{{ \sqrt{2} } }{ \sqrt{2} } [/tex]

[tex] x= \frac{ \sqrt{10} }{2} = \frac{1}{2} \sqrt{10} [/tex]