Question

6([tex]6(\frac{x+1}{8}-\frac{2x-3}{16})=3(\frac{3x}{4}-\frac{1}{4})-\frac{3}{8}(3x-2)[/tex]

Answer 1

Alaaaaaa de donde es esooo :0 ,perdón si me metí es q ps no sabía q era eso :(

Answer 2

6(x+1/8-2x-3/16)=3(3x/4-1/4)-3/8•(3x-2)
3(x+1)/4-3(2x-3)/8=9x/4-3/4-9/8x+3/4
3x-3/4-6x-9/8=9x/4-9/8x
2(3x+3)-(6x-9)=18x-9x
6x+6-6x+9=9x
15=9x
9x=15
X=5/3