Question

QUIZ (1412)
Materi: Integral

Tentukan hasil dari [tex] \displaystyle \int\limits_{3}^{6}{14x+12}~dx [/tex] !​

Answer 1

PEMBAHASAN

Integral Tentu

∫axⁿ dx = a/(n+1) xⁿ⁺¹ + C

∫(14x + 12) dx [6 3]

= 14/(1 + 1) x² + 12x

= 7x² + 12x

= 7(6² - 3²) + 12(6 - 3)

= 7 × 27 + 36

= 225

Answer 2

Verified answer

Jawab:

[tex]\displaystyle \int_{3}^{6}{14x+12}~dx = 225[/tex]

Penjelasan dengan langkah-langkah:

[tex]\displaystyle \int\limits_{3}^{6}{14x+12}~dx[/tex]

[tex]= \dfrac{14}{1+1} x^{1+1} + 12x^{0+1} ~]_3^{6}[/tex]

[tex]= \dfrac{14}{2} x^{2} + 12x^{1} ~]_3^{6}[/tex]

[tex]= 7x^{2} +12x ~]_3^{6}[/tex]

[tex]= (7(6)^{2} +12(6)) - (7(3)^{2} +12(3))[/tex]

= 324 - 99

= 225