Jika f(x) = x³ - 4x² + 4, f'(x) =
[tex](3)x^{3 - 1} - (2)4 {x}^{2 - 1} +( 0)4x^{0 - 1} \\ 3 {x}^{2} - 8x[/tex]
Jawaban:
f'(x) = 3x² - 8x
Penjelasan dengan langkah-langkah:
f(x) = ax^n
f'(x) = n.ax^n-1
maka
f(x) = x³ - 4x² +4
f'(x) = 3x² - 8x + 0(4x)^0-1
= 3x² - 8x
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Jika f(x) = x³ - 4x² + 4, f'(x) =
[tex](3)x^{3 - 1} - (2)4 {x}^{2 - 1} +( 0)4x^{0 - 1} \\ 3 {x}^{2} - 8x[/tex]
Verified answer
Jawaban:
f'(x) = 3x² - 8x
Penjelasan dengan langkah-langkah:
f(x) = ax^n
f'(x) = n.ax^n-1
maka
f(x) = x³ - 4x² +4
f'(x) = 3x² - 8x + 0(4x)^0-1
= 3x² - 8x