Question

QUIZ (1403)
Materi: Operasi Hitung

Tentukan hasil dari [tex] xy+x^2y+z^2 [/tex] jika diketahui :
[tex] x = 1 =y-z =\dfrac{ z}{ 3} [/tex]​

Answer 1

Verified answer

17

Penjelasan dengan langkah-langkah:

Diketahui:

[tex]\displaystyle\rm~ x = 1 =y-z =\dfrac{ z}{ 3}[/tex]

Ditanya:

[tex]\displaystyle\rm~ xy+x^2y+z^2 = ...?[/tex]

Penyelesaian:

x = 1

[tex]\displaystyle\rm~ \frac{z}{3} = 1 \\ \displaystyle\rm~z = 1.3 \\ \displaystyle\rm~z = 3[/tex]

y - z = 1

y - 3 = 1

y = 1 + 3

y = 4

maka,

[tex]\begin{aligned} \displaystyle\rm~xy+x^2y+z^2 \ \displaystyle\rm~ & = (1)(4) + ({1}^{2} )(4) + {3}^{2} \\ \displaystyle\rm~ & = 4 + 4 + 9 \\ \displaystyle\rm~ & = 17 \end{aligned} [/tex]

Answer 2

Penjelasan dengan langkah-langkah:

[tex]x = 1 \\ y - z = 1 \\ \frac{z}{3} = 1 \\ z = 3 \\ \\ y - z = 1 \\ y - 3 = 1 \\ y = 1 + 3 \\ y = 4 \\ \\ x =1 \\ y = 4 \\ z = 3[/tex]

[tex]xy + {x}^{2} y + {z}^{2} \\ (1)(4) + {(1)}^{2} 4 + {(3)}^{2} \\ 4 + 4 + 9 = 17[/tex]