Question

[tex]\displaystyle\bf~ \sqrt{ {81}^{ \frac{1}{2} } } - {2}^{0} = ...?[/tex]





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Answer 1

Materi : Bentuk Akar dan Pangkat

√(81¹/²) - 2⁰

= √(√81) - 1

= ⁴√81 - 1

= ⁴√(3⁴) - 1

= 3⁴/⁴ - 1

= 3¹ - 1

= 3 - 1

= 2

Semoga bisa membantu

[tex] \boxed{ \colorbox{darkblue}{ \sf{ \color{lightblue}{ answered\:by\: BLUEBRAXGEOMETRY}}}} [/tex]

Answer 2

Jawaban:

eksponen

[tex] \sqrt{ {81}^{ \frac{1}{2} } } - {2}^{0} = \sqrt{( {9}^{2}) {}^{ \frac{1}{2} } } - 1 \\ \sqrt{9} - 1 = 3 - 1 = 2[/tex]

nT:

[tex] {a}^{0} \ = 1 \\ ( {a}^{m} ) {}^{ \frac{n}{m} } = {a}^{n} [/tex]