Question

diketahui persamaan 4x² - 3X - 2 = 0 akar-akarnya P dan Q. Hitunglah
b.
[tex] \frac{p}{q - 2} + \frac{q}{p - 2} [/tex]
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Answer 1

Jawaban:

4x² - 3x - 2 = 0

maka

p + q = 3/4

p q = 2/4

p²q+pq²

= pq (p + q)

= -2/4 (3/4)

= -6/16

= -3/8