No. 1
[tex]\begin{aligned} \sf \frac{5}{8} \times 9 &= \sf \frac{5}{8} \times \frac{9}{1} \\ \sf &= \sf \frac{5 \times 9}{8 \times 1} \\ \sf &= \sf \frac{45}{8} \\ \sf &= \sf 5 \frac{5}{8} \end{aligned}[/tex]
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No. 2
[tex]\begin{aligned} \sf {8}^{2} \div {4}^{3} &= \sf { {(2}^{3} )}^{2} \div {( {2}^{2} )}^{3} \\ \sf &= \sf {2}^{3 \times 2} \div {2}^{2 \times 3} \\ \sf &= \sf {2}^{6} \div {2}^{6} \\ \sf &= \sf {2}^{6 - 6} \\ \sf &= \sf {2}^{0} \\ \sf &= \sf 1 \end{aligned}[/tex]
Penjelasan dengan langkah-langkah:
1) 5/8 × 9
= 45/8
= 5 ⅝
2) 8² ÷ 4³
= 4³ ÷ 4³
= 4⁰
= 1
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Verified answer
No. 1
[tex]\begin{aligned} \sf \frac{5}{8} \times 9 &= \sf \frac{5}{8} \times \frac{9}{1} \\ \sf &= \sf \frac{5 \times 9}{8 \times 1} \\ \sf &= \sf \frac{45}{8} \\ \sf &= \sf 5 \frac{5}{8} \end{aligned}[/tex]
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No. 2
[tex]\begin{aligned} \sf {8}^{2} \div {4}^{3} &= \sf { {(2}^{3} )}^{2} \div {( {2}^{2} )}^{3} \\ \sf &= \sf {2}^{3 \times 2} \div {2}^{2 \times 3} \\ \sf &= \sf {2}^{6} \div {2}^{6} \\ \sf &= \sf {2}^{6 - 6} \\ \sf &= \sf {2}^{0} \\ \sf &= \sf 1 \end{aligned}[/tex]
Penjelasan dengan langkah-langkah:
1) 5/8 × 9
= 45/8
= 5 ⅝
2) 8² ÷ 4³
= 4³ ÷ 4³
= 4⁰
= 1