Question

Rozwiąż równość [tex](a+2 \sqrt{2})^{2}=a^{2}+28\sqrt{2}+8[/tex]

Answer 1

Odpowiedź:

[tex]\displaystyle (a+2\sqrt{2} )^2=a^{2} +28\sqrt{2} +8\\a^{2} +4a\sqrt{2} +8=a^{2} +28\sqrt{2} +8\\4a\sqrt{2}=28\sqrt{2}/:4\sqrt{2} \\a=7[/tex]